Wednesday, January 27, 2010

Are Yoiu Supposed To Put Eye Cream On Your Eyelids Center Ellipse Or A Hyperbola - AL 2 - EASY BEST ANSWER?

Center Ellipse or a Hyperbola - AL 2 - EASY BEST ANSWER? - are yoiu supposed to put eye cream on your eyelids

How can I do?

(x 3) ^ 2 / 4 - (Y-3) ^ 2 / 9 = 1

I find the center of the ellipse or hyperbola to .. How can I determine what and how can I solve this problem - Please show me step yoiu'll and response and get the best answer!

3 comments:

Pi R Squared said...

Hello,

This equation has a minus sign between the groups, then this is the equation of a hyperbola. An ellipse has a "+" there.

The equation of a hyperbola is formed such

(x - h )².....( Y - K ²)
--------..-..--------- = 1, if the hyperbola to the left and right
.... From ²........... ²

(y - x )².....( k - h) ²
--------..-..--------- = 1, when the hyperbola opens up and down
.... From ²........... ²

However, the center is (h, k). "a" is the distance from each corner. "B" is the distance that point to see every corner of points need to move asymptotes. "B" is the distance perpendicular to the "distance" to new heights. The distance from the center to each focus is "C" and C is a ² + b ² = c ².

In this equation, the center (h, k) (-3.3). "A" 2, ie they move 2 of 2 left and center of the 2 vertices visit (-5.3) and (-1.3). "b" is 3 and thus increaseby 3 points from each corner to find the asymptotes decision. These are the points (-5.6) (-5.0) (-1.6) and (-1.0). An asymptote through the middle (-3.3) and points (-5.6) and (-1.0). The other asymptote passes through the center (-3.3) and points (-5.0) and (-1.6).

One side of the hyperbola will start (-5.3) and go left and drive along the 2 asymptotes. The other side of exaggeration (-1.3) and by the beginning and right along the 2 asymptotes.

Outbreaks are a ² + b ² = c ² by replacing "a" = 2 and b = 3:

2 ² + 3 ² = c ²
4 + 9 = c ²
13 = c ²
√ 13 = c

The houses are (-3 - √ 13.3) (-3 + √ 13.3).
This is about (-6.6,3) and (.6,3).

I hope that helps! :-)

Rizza M said...

Remember: (xh) ^ 2 / a ^ 2 - (yk) ^ 2 / b ^ 2 = 1 is the formula for the hyperbola (sign change under more and get an ellipse) (h, k) is the center. Its equation is therefore a hyperbola with center (-3,3): D

Distruggiu [CMA] said...

¼ (3 x) ^ 2 to 1 / 9 (y - 3) ^ 2 = 1

This is an ellipse

The general form of the ellipse

[(x - XO) ^ 2] / a ^ 2 - [(y - yo) ^ 2] / b ^ 2 = 1

Where and XO and I are the coord Center

C (xo, yo)

In this case we have

C (- 3, 3)

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